This series coated aluminum coil is anticorrosive and its production technology is good. The main ingredient in it is manganese element and the content is between 1.0% and 1.5%. 3000 series. color coated aluminum coil. thicknessmm. widthmm. color coated. TJLXKjqSx4ZC Equation No. 1bines all the factors that determine the surface area of the heat transfer device. A = Q/UT. A = area Q = total heat input required U = number describing the heat transfer coefficient or degree of influence of materials, agitation, viscosity and other system details. The U-factor is usually developed from past experience. T is a difference in temperature. There are actually two variations of T that will be used in calculations. The first (T1) is the difference in temperature of the solution in the tank before and after heating. For example, a solution is at 70F before heating and must be elevated to 140F: T1 = 140 - 70 =70F. This variation of T1will be used in the equation MCpDT. The second variation of temperature (T2) is between the heating medium (steam or hot water) and the final temperature of the solution. For example, suppose the final solution temperature is 140F and the temperature of the steam at 10 psi is 239F. T2 = 239 - 140 = 99F. The value of T2 var... See full list on In addition to Btus, other heat input is needed to make up for heat lost to the environment as well as to materials in the tank such as parts and racks. In most finishing systems, heat lost to the atmosphere is more important than heat lost to the work therefore, heat lost to work is usually ignored. However, if one were to pickle steel sheets that had been outside in very cold weather, an extra heating factor would have to be considered. Heat losses to the air can be calculated using information in Table II. The 3 × 10-ft tank surface loses 48,000 Btu/hr at 140F. This figure is derived from a heat loss figure of 1,600 Btu/hr/sq ft (Table II, 140F) multiplied by the sq ft (1,600 × 30=48,000). This means you would have to add an additional 48,000 Btu/hr to achieve the desired heat up. If the heat-up time were four hours, the total Btus/hr needed would be 179,040 (131,010 + 48,000). The total Btus/hr required is the final value of Q in the basic equation A = Q/UT. See full list on The next factor in calculating heat transfer surface area is the heat transfer coefficient or U factor. This varies depending on how well the tank is mixed or agitated and how viscous the solution is. For most watery finishing solutions Table III figures apply. For this example, steam will be used to heat the well-agitated tank. Therefore, a U factor of 150 will be used. Work temperature vs. media temperature. The second DT needed to calculate heat transfer surface area is the temperature difference between the material being heated and the media providing the heat. In finishing plants, heat is usually provided by hot water or steam. For this example, steam is used. Using the data in Table IV, T2can be determined as shown. Assuming a steam pressure of 10 psig, the temperature of the steam delivered to the f the solution will be heated to 140F, the T2= = 99F. See full list on Now that the basic values have been determined for all of the variables in equation A = Q/UT, we can solve it. In order to heat the solution to 140F in four hours you need the following: Q = 179,040 Btu/hr U = 150 T2 = 99F. Completing the equation A = 179,040/150 × 99 = 170,040/14,850 = 12.06 sq ft. See full list on When the surface area of a heat transfer device has been calculated, the next consideration is the configuration of the device. In many finishing plants in-tank heating/cooling coils are used. When a coil is to be immersed, there are several major considerations. Coils must be sized and installed so they do not interfere with material moving into or out of the tank. The mostmon form of damage to an in-tank coil is mechanical. In tanks with current-carrying racks, accidental contact between a rack and coil may cause an electrical arc, resulting in a hole in the coil. Coils should be installed to ensure the entire coil body is immersed. This assures that the rated heat transfer surface is operating at maximum effectiveness. See full list on A typical style is shown in Fig. 1. In a typ outside diameter tubing is centers betweeudes an inlet and outlet riser for the heating medium. Before determining the length and width of the coil, measure the length of the tank wall and the solution depth. For this example, the tank walls are 3-ft wide and 10-ft long, and the solution is 4-ft deep. Considering each possibility, the coil would need to be sized to fit within an area that is 3 × 4 ft or one that is 10 × 4 ft. In sizing heat transfer coils it is important to select the configuration with the smallest width and longest lengthpatible with tank size to provide the best heat distribution. Using data found in Table V, you can determes provides 13.2 sq ft of surface area. Moving further down the chart you find a coil of 13es and a... See full list on Why is it important to calculate surface area when determining the size of heating coils? Heat transfer devices, particularly ones fabricated from a costly material such as titanium or stainl most heat transfer devices are priced according to size, it simply does not pay to purchase larger devices than are necessary to aplish the task. Using the information in this article will help determine how much area you will need after you establish how long heat up should take and what temperature you must maintain. A little pencil pushing can go a long way toward improving operating efficiency and lowering heat transfer equipment costs To learn more visit RIGHTech Fabrications. See full list on 9Yh4BEXlMnDN In this case the heat exchanger would be designed by the normal methods and will not be covered further in this chapter. (See Heat Exchangers.) A jacket may be either a full conventional jacket, a dimpled jacket, or a half-pipe jacket, often called a limpet coil, as illustrated in Figure 1a, Figure 1b and Figure 1c. The designs arepared by ... AEfMZuYAldcQ Aug 01, 2019 · A typical organic coil coating line consists of decoilers, entry strip accumulator, cleaning, chemical pretreatment, primer coat application, curing, final coat application, curing, exit accumulator and recoilers. Coil-coating lines vary greatly in size, with rated outputs between: 3,000 tons per annum and 200,000 tons per annum of coated metal, 7MpNI2VrnI76
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